1. Find the power absorbed by a 500-ohm resistor when it is connected directly across a constant 50 – source .

Answer : 5 watt

   

2. A voltage source v = 100 cos t V is connected across a resistor of 2 Ω.find the power delivered to the resistor

3.

 R1 =2000 Ω R2 =4000 Ω R1 =8000 Ω

Is = 30 mA

Answer :

P1 = Ir x R2 =  x (2000 Ω) = 1,8W

P2 = Ir x R2 =  x (4000 Ω) = 3,6 W

P3 = Ir x R3 =  x (8000 Ω) = 7,2 W

4.